30m^2+10=28m+4

Solution for 30m^2+10=28m+4 equation:

30m^2+10=28m+4

We move all terms to the left:

30m^2+10-(28m+4)=0

We get rid of parentheses

30m^2-28m-4+10=0

We add all the numbers together, and all the variables

30m^2-28m+6=0

a = 30; b = -28; c = +6;
Δ = b2-4ac
Δ = -282-4·30·6
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-8}{2*30}=\frac{20}{60}
=1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+8}{2*30}=\frac{36}{60}
=3/5
$